Question

the sum of two number is 8 and their differences is 4.Find the numbers ​

Answer 1

Answer:

let two no.s be x and y

case-1

x+ y = 8

case -2

x- y = 4

using elimination method 1,2

x+y = 8

x-y = 4

————

2x = 12

x = 6

put value of x in 1

6+y = 8

y = 8-6 = 2

two no.s are 6 and 2

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Answer 2

Answer :

• Sum of two numbers is 8

• Difference of two numbers is 4

We have to find : The numbers

• Let one number be x and another be y

• According to the question :

$\implies \sf x\:+\:y\:=\:8 --- eq(1)$

$\implies \sf x\:-\:y\:=\:4 --- eq(2)$

• Now simply add up the equations :

$\implies \sf x\:+\:y\:+\:x\:-\:y\:=\:8\:+\:4$

$\implies \sf 2x\:=\:12$

$\implies \sf x\:=\:\dfrac{12}{2}$

$\implies \sf x\:=\:6$

• One number is 6

We can find another one by substituting in equation 1 :

$\implies \sf 6\:+\:y\:=\:8$

$\implies \sf y\:=\:8\:-\:6$

$\implies \sf y\:=\:2$

• Second number is 2

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