Question

please anyone here to help me . Don't copy from Google as it is not having answer.

find value of x in 1/x+4 - 1/x-7 = 30
please please find answer​

Answer 1

1 Or 2 roots of given Quadratic equation.

Explanation:

Given

\frac{1}{x+4}-\frac{1}{x-7}=\frac{11}{30}

x+4

1

−

x−7

1

=

30

11

\implies \frac{[x-7-(x+4)]}{(x+4)(x-7)}=\frac{11}{30}⟹

(x+4)(x−7)

[x−7−(x+4)]

=

30

11

\implies\frac{x-7-x-4}{x^{2}-7x+4x-28}=\frac{11}{30}⟹

x

2

−7x+4x−28

x−7−x−4

=

30

11

\implies\frac{-11}{x^{2}-3x-28}=\frac{11}{30}⟹

x

2

−3x−28

−11

=

30

11

Do the cross multiplication, we get

=> 30 = 11(x²-3x-28)/(-11)

=> 30 = -(x²-3x-28)

=> x²-3x-28+30 =0

=> x²-3x+2=0

Splitting the middle term, we get

=> x²-1x-2x+2 =0

=> x(x-1)-2(x-1)=0

=> (x-1)(x-2)=0

=>x-1 = 0 or x-2 = 0

=> x = 1 or x = 2

Therefore,

Roots of the given quadratic equation are 1 , 2

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Answer 2

Answer:

$\frac{1}{x} + 4 - \frac{1}{x} - 7 = 30$

$Taking\ L.C.M\ of\ all\ terms\ on\ left\ side:-$

$\frac{1\ +\ 4x\ -\ x-\ 7x}{x} = 30$

$\frac{1\ -\ 4x}{x} = 30$

$1\ -\ 4x = 30x$

$1  = 30x\ +4x$

$1 = 34x$

$\frac{1}{34} = x$

$⇒ x = \frac{1}{34}$

Step-by-step explanation:

Hope it helsp you buddy :)