Please anyone solve this by sending a picture showing the solution.
Attachments:
Answers
Answered by
1
This is ur ans hope it will help you in case of any doubt comment below
Attachments:
tnwramit1:
have u got it or not
why have you taken perimeter of circle as pi x r
as we know circumference of circle is 2 pi r
then for semi circle it is pi r
ohh
hmmm
Now I got it
ok
Thank you for your help..
np
Answered by
2
ANSWER
............
Diameter of the circle i.e., PQRS = 2 * 6 = 12 cm
PORS is divided into 3 parts,therefore PQ = RS = QR = 1/3 *12 = 4 cm
radius = 2 cm
area of semi circler with PQ as diameter = 1/2/pie r2
1/2 * 22/7 * 2222/7 * 244/7 ... ( i )
Length of QS = 2/3 * 12 =8 cm
Radius = 4 cm
area of semi circle with QS as diameter = 1/2 pie r
1/2 * 22/7 * 42 22/7 * 2*422/7 * 8176/7 ... ( ii )
area of semicircle with PQRS as diameters = 1/2 pie r2
1/2 * 22/7 * 12 *1222/7 * 6 *12 22/7 * 721584 / 7 ... ( iii )
area of semicircle with PQRS as diameter - area of semicircle with QS as diameter + area of semi circle with PQ as diameter
1584/7 - 176/7 + 44/7
= 1408 / 7 + 44/7
= 1452/ 7
= 207. 428571
............
Diameter of the circle i.e., PQRS = 2 * 6 = 12 cm
PORS is divided into 3 parts,therefore PQ = RS = QR = 1/3 *12 = 4 cm
radius = 2 cm
area of semi circler with PQ as diameter = 1/2/pie r2
1/2 * 22/7 * 2222/7 * 244/7 ... ( i )
Length of QS = 2/3 * 12 =8 cm
Radius = 4 cm
area of semi circle with QS as diameter = 1/2 pie r
1/2 * 22/7 * 42 22/7 * 2*422/7 * 8176/7 ... ( ii )
area of semicircle with PQRS as diameters = 1/2 pie r2
1/2 * 22/7 * 12 *1222/7 * 6 *12 22/7 * 721584 / 7 ... ( iii )
area of semicircle with PQRS as diameter - area of semicircle with QS as diameter + area of semi circle with PQ as diameter
1584/7 - 176/7 + 44/7
= 1408 / 7 + 44/7
= 1452/ 7
= 207. 428571
Similar questions