Question

please anyone solve this problem given above​

Answer 1

Answer:

Correct answer is

24.06 min

Explanation:

The rate law expression for the first order reaction is =K×[A].

Substitute values in the above expression.

0.04=K[A] 10 ___(1)

0.03=K[A] 20 ___(2)

Divide equation (1) by equation (2)

[A]  10/ [A]  20  =  0.04 /0.03 =  4/3

At 10 min, the expression for the rate constant will be

t=   (2.303/k)log  [A]  10/ [A]20

10=2.303/k log 4/3

Hence, the rate constant K=2.303/10 log 4/3 =0.0288min  −1

The half life period is t  base 1/2 ​ =0.693/k=24.06 min (inv)-1

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