Please help in finding the answer
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Answered by
1
Step-by-step explanation:
z^2 = (2^2-2*i*2+(I) ^2)
= 4-4i-1
=3-4i
w-i = 1+3i-i =1+2i
1/w = 1/(1+2i)
so now
a+ib = -1-2i
conjugate of a+ib = -1+2i
modulus = √(1+4)=√5
Answered by
4
Given complex numbers are
and
Now, Consider
Let we assume that
On substituting the values of z and w, we get
On rationalizing the denominator, we get
Hence,
and
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