Question

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Answer 1

Step-by-step explanation:

Given that, the point P(2,1) lies on the line segment joining the points A(4,2)and B(8,4), which shows in the figure below:

P (2.1)

A (4,2)

B (8,4)

Now, distance between A(4,2)and (2,1),AP = (2-4)² + (1 - 2)²

[..distance between two points two points

(x₁, y₁) and B(x 2 ,y 2 ),d= sqrt (x 2 -x 1 )^ 2 +(x 2 -y 1 )^ 2 ]

(−2)² + (−1)² = √√4+1 √5 = Distance between A(4,2) and B(8,4)

AB = sqrt((8 - 4) ^ 2 + (4 - 2) ^ 2)

√(4)² + (2) ² Distance between B(8,4) and P(2,1), BP

=

√16+4

(8 - 2)² + (4-1)²

+3² /36 + 9 = √(4-1)²

=

V

/20 = 2√//5

= V

.. AB = 2√5 = 2AP AP AB 2

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Answer 2

Answer: B

Step-by-step explanation: