Question

please briefly explain me​

Answer 1

Step-by-step explanation:

$(\frac{4}{7} )^{3}$ ÷ $(\frac{7}{4} )^{5}$ = $(\frac{4}{7} )^{x - 2}$

= >$(\frac{4}{7} )^{3}$ ÷ $(\frac{4}{7} )^{-5}$ = $(\frac{4}{7} )^{x-2}$

=> $(\frac{4}{7} )^{3- (-5)}$ = $(\frac{4}{7} )^{x-2}$                         [∵ $a^{x}$ ÷ $a^{y}$ = $a^{x-y}$]

=> $(\frac{4}{7} )^{3+5}$ = $(\frac{4}{7} )^{x-2}$

As the bases are same therefore,

=> 3+ 5 = x - 2

=> 8 = x - 2

=> x-2 = 8

=> x = 8 + 2

=> x = 10 (Ans)

Answer 2

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