Question

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Answer 1

Answer:

i) 3a-2b=3(-1)–2(2)= –3–4= –7

ii) –5ab+2a= –5(–1)(2)+2(–1)=10-2=8

iii) 3b²–4a=3(2)²–4(–1)=12+5=17

Answer 2

Question

For a =-1 and b=2 , evaluate the following expressions:-

(I) 3a-2b

(ii)-5ab+2a

(iii)3b²-4a

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

Step by step explanation

1.Write the value of a and b in brackets form.

=>3(-1)-2(2)

2.Now, Expanding the expression .

=>3×-1-2×2

=>-3-4

= -7

(ii)-5ab+2a

=>-5(-1)(2)+2(-1)

=>-5×-1×2 +2×-1

minus minus gets cancelled and it becomes positive.

=>5×2+(-2)

=>10-2

=8

(iii)3b²-4a

=>3(2)²-4(-1)

=>3×2×2-4×-1

=>3×4+4

=>12+4

=16