Question

please can anyone solve it i will mark it the brainliest ........​

Answer 1

Answer:

Hi ,

LHS =( SecA - tanA)/(secA + tanA)

=[(SecA - tanA)(secA-tanA )]/[secA+tanA)(secA-tanA )]

= ( SecA - tanA )²/[ sec² A - tan² A )

= ( secA - tanA )²/1

[ Since sec²A - tan² A = 1 ]

= Sec² A + tan² A - 2tanAsecA

= 1 + tan² A + tan² A - 2secAtanA

= 1 + 2tan²A - 2secAtanA

= RHS

I hope this helps you.

: )

you can put A=@

Step-by-step explanation:

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