Question

please can someone answer this ​

Answer 1

Step-by-step explanation:

pathyagoros theorem

Show that :

AD2 = AB2 - BD2 ( | )

∆ACD,

AC2 = AD2 + DC2

AD2 = AC2 - DC2 ( || )

AB2 - BD2 = AC2 - DC2 from (|) and (||)

AB2 + DC2 = AC2 + BD2

prove this AB2 + CD2 = AC2 - BD2 by pathyagoros theorem.

thanku please mark as brainlist

Answer 2

Answer:

Step-by-step explanation:

In ΔABD, AB² = AD² + BD² ... ∵ Pythagorean Theorem ( spelling error )

∴ AD² = AB² - BD² ... ( I )

In ΔACD, AC² = AD² + DC² ... ∵ Pythagorean Theorem

∴ -AD² = AC² - AC² ... ( II )

∴ AB² - BD² = AC² - CD² ... from ( I ) and ( II )

∴ AB² + CD² = AC² + BD² Q.E.D