Math, asked by udita678, 1 year ago

Please can someone answer this with all the steps?

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Answered by Joshuawoskk
1
LHS, using identities sinC +sinD = 2sin(C+D)/2 cos(C-D)/2 and

CosC –cosD = - 2sin(C+D)/2 sin(C-D)/2

(2sin(cos)]sinx + [ -2sin(sin(]cosx

(2sin2x.cosx)sinx + (-2sin2x.sinx)cosx

= 2sin2x.sinx.cosx - 2sin2x.sinx.cosx

= 0

= RHS

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