Question

Please can u solve this one.

Answer 1

Hi...☺

Here is your answer...✌

sinθ = a/b = P/H

let , P = ak and H = bk

Using Pythagoras theorem

B² = H² - P²

B² = b²k² - a²k²

B = √[ k² ( b² - a² ) ]

B = k (b² - a²)

Now,

secθ + tanθ = H/B + P/B

= bk / k(b² - a²) + ak / k(b²-a)

= b / (b² - a²) + a / (b² - a²)

= (b + a) / (b² - a²)

= (b + a) / (b + a) (b - a)

= 1 / (b - a)