Math, asked by rupalikondekar1, 8 months ago

Please differentiate the following function ​

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Answers

Answered by Anonymous
2

Step-by-step explanation:

hope it helps u.................

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Answered by Anonymous
0

Step-by-step explanation:

dy/dx = d(1+x^2)(1+x^4)........(1+x^2n)/d(x)

→ dy/dx = (1+x)` •(1+x^2)......(1+x^2n)+

(1+x)•(1+x^2)`•........(1+x^2n) + (1+x)(1+x^2)......(1+x^2n)`

Differentiation of constant is 0

→dy/dx = 1(1+x2)....(1+x^2n)+(1+x)•2x•......(1+x^2n)+ (x+1)(1+x^2n)......2n•x^(2n-1)

Put x = 0

Because, As per question , x=0

dy/dx=1

Thus ,

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