Question

Please do 4tn no summ

Answer 1

tan theta = 3/4
cot theta 4/3

${cot}^{2} theta \: = 16 \div 9 \\ {coscec}^{2} theta \: = 16 \div 9 \\ + 1 \\ {cosec}^{2} \: theta \: = \ 25 \div 9 \\ cosec \: theta = \sqrt{25 } \\ 1 \div sin \: theta = 5 \div 3 \\ \\ sin \: theta \: = 3 \div 5 \\ sq \: both \: side \\ {sin}^{2} theta \: = 9 \div 25 \\ {cos}^{2} theta = 9 \div 25 + 1 \\ cos \: theta \: \sqrt{36 \div 25 } \\ cos \: theta \: = 6 \div 5 \\ 1 \div sec \: theta \: = 6 \div 5 \\ sec \: theta = 5 \div 6$
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