Question

please do all with statement..otherwise I will reported
a)c³ b) (2b²) ...etc fast plss​

Answer 1

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(c2=ab)x2−2(a2−bc)x+(b2−ac)=0

comparing with Ax2+Bx+C=0, we get

 ∴A=(c2−ab),B=−2(a2−bc),C=(b2−ac)

Roots of the quadratic eqn. are equal

⇒D=0

⇒B2−4AC=0

⇒B2−4AC=0

⇒B2=4AC

⇒[−2(a2−bc)2]=4(c2−ab)(b2−ac)

⇒4(a2−bc)2=4(c2−ab)(b2−ac)

⇒a4+b2c2−2a2bc=b2c2−ac3−ab3+a2bc

⇒a4+ab3+ac3=3a2bc.

⇒a(a3+b3+c3−3abc)=0.

∴a=oora3+b3+c3=3abc.

Answer 2

Answer:

a=1000

b=4

c=1111

b=1

e=-21000

f-=72

g=27

h=-6

i=109

j=97

• please mark me as brainliest..❤