Question

Please do answer it guys
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Answer 1

Answer:

If points A(2,3),B(4,k) and C(6,-3) are collinear

then their area will be 0

So,

area of three points ( or triangle)=

½[2(k+3) +4(-3-3) +6(3-k)= 0

½[2k + 6 +4(-6) +18 - 6k]= 0

½[2k +6 -24+ 18 - 6k] = 0

1[2k +24-24 - 6k] = 0×2

-4k =0

k= 0

Therefore, for k= 0 all three points are collinear