Math, asked by vijaypanghal35, 9 months ago

please do fast it's urgent please it's my holidays homework ​

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Answered by karannnn43
0

 {6}^{n} can \: not \: end \: with \: digit \: 0 \: becuz \: for \: ending \: wih \: digit \: 0 \: its \: prime \: factorisation \: must \: contain \: 5 \:

But , here ,

 {6}^{n}  =  {(2 \times 3)}^{n}

Answered by sasikalajanasree
0

hi my name is janasree

did Shiv say u that he have gf

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