Please do it............
Attachments:

devkumardash:
name of chapters
Answers
Answered by
1
Let ABCD is a rectangular plot having a measurement of 40 m long and 15 m front.
Length of inner-rectangle, EF = 40 – 3 – 3 = 34 m and breadth of inner-rectangle, FG =15 – 2 – 2 = 11 m
∴ Another rectangle EFGH will be formed inside the rectangle ABCD
∴ Area of inner rectangle, EFGH = Length x Breadth
= EF x FG = 34 x 11 = 374 m2
[∴ area of a rectangle = length x breadth]
Hence, the largest area where the house can be constructed in 374 m2.
sorry for graph i think you cant understood without graph.
Length of inner-rectangle, EF = 40 – 3 – 3 = 34 m and breadth of inner-rectangle, FG =15 – 2 – 2 = 11 m
∴ Another rectangle EFGH will be formed inside the rectangle ABCD
∴ Area of inner rectangle, EFGH = Length x Breadth
= EF x FG = 34 x 11 = 374 m2
[∴ area of a rectangle = length x breadth]
Hence, the largest area where the house can be constructed in 374 m2.
sorry for graph i think you cant understood without graph.
Attachments:

Similar questions