Question

Please do it fast...​

Answer 1

$\huge \bf \underline{answer}$

Given = AB//CD

RTP = AOB~DOC

Proof = AB ~ CD {Given that they are parrallel}

<O= <O {vertically opposite angles}

<A = <D {Interior opposit angles are equal}

...Hence proved

Answer 2

$\displaystyle\sf{Given\:,$

$\displaystyle\sf{AB||CD$

$\displaystyle\sf{In \triangle AOB \:and\: \triangle DOC\:,$

• $\displaystyle\sf{<AOB = <DOC\:(Vertically\:opposite\:angles)$

• $\displaystyle\sf{<OAB = <ODC\:(Alternate\:angles)$

• $\displaystyle\sf{<ABO = <DCO\:(Alternate\:angles)$

$\boxed{\displaystyle\sf{\therefore \triangle AOB \sim \triangle DOC\:(AAA\:similarity)}}$