Question

please do it fast its very urgent​

Answer 1

Answer:

For gun m1=3kg For bullet m2=30g=0.03kg,v2= 100m/s By law of conservation of momentum m1*v1= m2 *v2 3*v1 =0.03*100 v1 =0.03*100/3 (i) The velocity with which the gun recoils=v1=1 m/s Acceleration of bullet=v-u/t 100-0/0.03=3333.33m/s2 (ii)The force exerted on gunman due to recoil of the gun=F=ma=0.03*3333.33=100 N