Please do it in notebook and send
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Step-by-step explanation:
In ∆oBC and ∆ oAD
<B = <A = 90°
( as AD and BC are perpendiculars )
and oB =oA (given)
and <BOC = < AOD
( vertically opposite angles )
∆ oBC = < oAD
( by AAS congruence rule )
= oA =oB ( by c.p.c.t)
= CD bisects AB
hence proved
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