Question

Please do Question 8

Answer 1

see the attachmenhope it helps

please mark as BRAINLIEST

Answer 2

ANSWER-:

GIVEN

• f(X)=x^5-a²x³+2x+a-3
• zero of polynomial=x-a
• so,X=a

putting value of x in px to find the value of a

here x=a

$↪ {x}^{5} - {a}^{2} {x}^{3} + 2x + x - 3 \\ \\↪ {a}^{5} - {a}^{2} {a}^{3} + 2a + a - 3 \\ \\ ↪3a - 3 \\ \\ ↪3a = 3 \\ \\ ↪a = 1$

hence:-

• the value of a=1