Question

please do question ii and iv only in notebook with proper explanation please help me with ​( please

Answer 1

Answer:

• (ii) Area = 48 cm²
• (iv) width = 4 cm

Step-by-step explanation:

(ii)

Given,

• Length of the rectangle, l = 8 cm
• Width of the rectangle, b = 6 cm

To find,

• Area of the rectangle

Solution,

     $\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 8 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 6 cm}\end{picture}$

we know

Area of the rectangle = length × breadth

➙ Area = l × b

➙ Area = 8 cm × 6 cm

➙ Area = 48 cm²

∴ The area of the rectangle = 48 cm²

(iv)

Given,

• Area of the rectangle = 28 cm²
• length of the rectangle, l = 7 cm

To find,

• width of the rectangle, b = ?

Solution,

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 7 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large b cm}\end{picture}$

we know,

Area of the rectangle = length × breadth

➙ Area = l × b

➙ 28 cm² = 7 cm × b

➙ b = 28 cm²/7 cm

➙ b = 4 cm

∴ The width of the rectangle = 4 cm

Answer 2

$\huge\sf\underline\red{Solution}$

2) Given, Length is 8cm

Width is 6 cm

Area=?

$\huge\bf\underline\red{Formula}$

Area of rectangle = length × Breadth

So, Area = 8cm × 6cm

Area = 48cm²

______________________________________________________

4) Given that

Area of rectangle is 28 cm²

Length is 7cm

Width =? b

Same formula....

Area of rectangle = length × breadth

28cm² = 7cm × b

b = 28cm²/7cm

b = 4cm

So, breadth of rectangle is 4cm

hey mate Width or breath same only...