PLEASE DO QUESTION NO. 31
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Answered by
2
12ky²+8ky-20k
take 4k common
4k(3y²+2y-5)
4k(3y²-3y+5y-5)
4k[3y(y-1)+5(y-1)]
4k(y-1)(3y+5)
dimensions are length =4k
breadth = (y-1)
height=(3y+5)
hope this helps
take 4k common
4k(3y²+2y-5)
4k(3y²-3y+5y-5)
4k[3y(y-1)+5(y-1)]
4k(y-1)(3y+5)
dimensions are length =4k
breadth = (y-1)
height=(3y+5)
hope this helps
TANU81:
Thank you very much.........
ur welcome
Answered by
1
(a-b)^3
= 8a^3=(2a)^3
= b^3= (b)^3
So, (2a-b)^3 is the factor
= 8a^3=(2a)^3
= b^3= (b)^3
So, (2a-b)^3 is the factor
Sorry for the inconvenience.. plz report my answer
But which question u have do
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