Please do step by step in a box.
Answers
Explanation:
(a) P
C
l
5
+
H
2
O
=
H
3
P
O
4
+
H
C
l
Left side:
P = 1
Cl = 5
H = 2
O = 1
Right side:
P = 1
Cl = 1
H = 3 + 1 (DO NOT ADD IT UP YET)
O = 4
Start balancing the easiest element, in this case, the Cl.
Left side:
P = 1
Cl = 5
H = 2
O = 1
since
H
C
l
is a substance, you need to also multiply its H by 5.
Right side:
P = 1
Cl = 1 x 5 = 5
H = 3 + (1 x 5) = 8
O = 4
P
C
l
5
+
H
2
O
=
H
3
P
O
4
+
5
H
C
l
Now the H atom on the left side is not balance with the right side, we have to multiply the H on the left side by 4.
Left side:
P = 1
Cl = 5
H = 2 x 4 = 8
O = 1 x 4 = 4
Again, since
H
2
O
is a substance, you also need to multiply its O by 4.
Right side:
P = 1
Cl = 1 x 5 = 5
H = 3 + (1 x 5) = 8
O = 4
P
C
l
5
+
4
H
2
O
=
H
3
P
O
4
+
5
H
C
l
1
To balance PCl5 + H2O = H3PO4 + HCl you'll need to be sure to count all of atoms on each side of the chemical equation. Once you know how many of each type of atom you can only change the coefficients (the numbers in front of atoms or compounds) to balance the equation for Phosphorous pentachloride + Water.
for all
To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.
Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
Ionic charges are not yet supported and will be ignored.
Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
Compound states [like (s) (aq) or (g)] are not required.
You can use parenthesis () or brackets [].