Question

please do the requested questions in notebook ​

Answer 1

Answer:

Step-by-step explanation:

→ If any number ends with the digit 0, it should be divisible by 10 or in other words, it will also be divisible by 2 and 5 as 10 = 2 × 5

→ Prime factorisation of 6n = (2 ×3)n

→ It can be observed that 5 is not in the prime factorisation of 6n.

→ Hence, for any value of n, 6n will not be divisible by 5.

→ Therefore, 6n cannot end with the digit 0 for any natural number n.

Answer 2

refer to the attachment!!!!