Math, asked by corvuscrone, 9 months ago

Please do this! And no fake stuff

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Answered by meowwww75
1

Hey !

Express the given equation in Slope-Intercept Form, which is given as

\fbox{\huge{\mathbf{y = mx+c}}}

where \textsf{m} is slope

and \textsf{c} is the y-intercept

\\\\

(3) Given,

y-1 = -2x

y = (-2)x+1

Slope m = -2 ;

y -intercept c = 1

\\\\

(4) y = -x

=> y = (-1)x + 0

Slope m = -1

y-intercept = 0

\\\\

(5) y = 7-3x

=> y = (-3)x+7

Slope m = -3

y-intercept c = 7

\\\\

(6) y/2 = x

=> y = (2)x+0

Slope m = 2

y-intercept c = 0

\\\\

(7) 5+y = 1+2x

=> y = (2)x +(1-5)

=> y = (2)x +(-4)

Slope m = 2

y-intercept c = -4

\\\\

(8) y/3 = x/6

Cross Multiply

=> 6y = 3x

=> 2y = x

=> y = (1/2)x +0

Slope m = 0.5

y-intercept c = 0

\\\\

(9)y/2 = x+1

=> y = (2)x+2

Slope m = 2

y-intercept c = 2

\\\\

(10) y+x = 3+x

=> y = 3

Slope m = 0

y-intercept c = 3

\\\\

Together we go Far. Be brainly

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