Question

please do this please .............​

Answer 1

Answer:

(i) In ∆PQR and ∆DEF,

angle pqr = def (right angle)

and pr =df = 6cm (hypotenuse)

hence ∆PQR congruent with∆DEF

(ii) In ∆ACB and ∆ADB,

angle acb =adb (right angle)

and ab =ab = 3.5 cm (hypotenuse)

hence ∆ACB is congruent with∆ADB

Do remaining as it is on your own