Question

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Answer 1

Answer: x²y³(2+x)

Step-by-step explanation:

x²y³+3x³y³+3x²y³-2(x³y³+x²y³)

= x²y³+3x³y³+3x²y³-2x³y³-2x²y³

= (x²y³-2x²y³+3x²y³)+(3x³y³-2x³y³)

= 2x²y³+x³y³

=x²y³(2+x)