please do this sum tomorrow is my exam
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silu12:
sample space is 4
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Total number of coins tossed = 2
The sample space n(S) = {HH,HT,TH,TT} = 4.
Let A be the event of getting atleast one head.
n(A) = {HH,TH,HT} = 3.
Required probability P(A) = n(A)/n(S) = 3/4.
It is a compound event because it has more than one possible outcome.
Hope it helps!
Answered by
0
Sample space =4
P(A)=3/4
P(A)=3/4
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