Question

Please do with procedure.​

Answer 1

Answer :- x = 3

$\bf\huge\underline{\underline{ Answer :- }}$

• $\frac{7x - 1}{4} - \frac{1}{3} \bigg(2x - \frac{1 - x}{2} \bigg) = \frac{10}{3}$

• $\red{\implies}\frac{7x - 1}{4} - \frac{1}{3} \bigg( \frac{4x - 1 - x}{2} \bigg) = \frac{10}{3}$

• $\red{\implies} \frac{7x - 1}{4} - \frac{1}{3} \bigg( \frac{3x - 1}{2} \bigg) = \frac{10}{3}$

• $\red{\implies}\frac{7x - 1}{4} - \frac{3x + 1}{6} = \frac{10}{3}$

• $\red{\implies}\frac{6(7x - 1) - 4(3x + 1)}{24} = \frac{10}{3}$

• $\red{\implies}\frac{42x - 6 - 12x - 4}{24} = \frac{10}{3}$

• $\red{\implies}\frac{30x - 10}{24} = \frac{10}{3}$

• $\red{\implies}30x - 10 = \frac{10 \times 24}{3}$

• $\red{\implies}30x - 10 = 80$

• $\red{\implies}30x = 90$

• $\red{\implies}x = \frac{90}{30}$

• $\red{\implies}x = \frac{9}{3}$

• $\red{\implies}x = 3$