Question

please don't put irrelevant ANS
Prove that 1 upon 3 minus root 8 minus 1 upon root 8 minus root 7 + 1 upon root 7 minus root 6 minus 1 upon root 6 minus root 5 + 1 upon root 5 minus 2 is equal to 5 show in step explainatiomln​

Answer 1

(1/3-√8)-(1/√8-√7)+(1/√7-√6)-(1/√6-√5)+(1/√5-2)=5

Taking left hand side...

(1/3-√8)-(1/√8-√7)+(1/√7-√6)-(1/√6-√5)+(1/√5-2)

=(1/3√8×3+√8/3+√8)-(1/√8-√7×√8+√7/√8+√7)+(1/√7-√6×√7+√6/√7+√6)-(1/√6-√5×√6+√5/√6+√5)+(1/√5-2×√5+2/√5+2)

=(3+√8/9-8)-(√8+√7/8-7)+(√7+√6/7-6)-(√6+√5/6-5)+(√5+2/5-4)

=(3+√8)-(√8+√7)+(√7+√6)-(√6+√5)+(√5+2)

=3+√8-√8-√7+√7+√6-√6-√5+√5+2

=3+2=5

Hope ti helps you......

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