Question

please don't spam...

find x....​

Answer 1

✷ANSWER:-

In Triangle ACO,

If we consider angle AOC as A,

We are already given 2 angles

40 degree and 100 degree.

☞Now by Angle sum property:-

→A+40+100°=180°

→A=180°-140°

→A= 40°

Now in Triangle OXB,

Angle XOB will be 40°

(Vertically opposite angles with angle AOC or A)

So,

Again by Angle sum property,

→x+110°+40°=180°

→x=180°-150°

→x= 30° is the answer.

☞points to be noted....

◉This question is based on Angle sum property of Triangle

◉All three sides of angle of Triangle must be equal to 180°

Answer 2

Answer:

$\huge\underline\bold\red{AnswEr}$

In Triangle ACO,

If we consider angle AOC as A,

We are already given 2 angles

40 degree and 100 degree.

☞Now by Angle sum property:-

→A+40+100°=180°

→A=180°-140°

→A= 40°

Now in Triangle OXB,

Angle XOB will be 40°

(Vertically opposite angles with angle AOC or A)

So,

Again by Angle sum property,

→x+110°+40°=180°

→x=180°-150°

→x= 30° is the answer.