Question

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Answer 1

Question:-

The dimensions of a box are 22cm×11cm×3cm. It is to be covered with a brown paper. If each box requires 164cm² of more paper for folding, how much paper is required to wrap 85 such boxes ?

Answer:-

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⇒Given:-

⇒length of the box = 22cm

⇒breath of the box = 11cm

⇒Height of the box = 3cm

⇒Solution:-

⇒The box is covered on 3 faces, which are bottom, top and back.

➡️area of bottom = length × breath

⇒22 cm × 11cm

⇒242 cm ²

➡️area of the top = area of the bottom =242 cm²

➡️area of back = length × height

⇒22 × 3 = 66cm²

⇒Total area = 242cm²+242cm²+66cm²+164cm² = 714 cm²

➡️area of paper required for 85 box = 714 × 85 = 60690 cm ²

➡️hence, 60690 cm ² is required to cover 85 such boxes .

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Question:-

Draw a line segment AB=1cm,Find a point Q on it such that AQ= 2/5 QB. measure the smaller part [ use the diagram to show the answer as per the provided question]

Solution:-

• Check the attachment, solution given.

• So after solving we are getting

• ➡️QB=5 cm
• ➡️AQ=2cm

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Correct Question:-

If, in the given figure AB।। CD, CD।। EF and x:y=3:7, then find the value of "x" as -

Solution:-

• Refer to the second attachment for the third question"s answer.

• So, by solving we got x = 126°

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Note:-

• The first attachment is for the second question's answer.

• The second attachment is for the third question's answer.

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