please evaluate step wise
√((7)-4√3)
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√[(7)-4√3) ]
= √[((7)-2√12)] [2=√4, hence √3*√4=√12]
now, 7=3+4 and 12=3*4
= √[(3+4)-2√3*√4)]
= √[3-2√3*√4+4]
= √[(√3)²-2√3*2+(2)²]
= √[(√3-2)²]
= √3-2
Hope it helped.
= √[((7)-2√12)] [2=√4, hence √3*√4=√12]
now, 7=3+4 and 12=3*4
= √[(3+4)-2√3*√4)]
= √[3-2√3*√4+4]
= √[(√3)²-2√3*2+(2)²]
= √[(√3-2)²]
= √3-2
Hope it helped.
bhattisingh111:
Thanks
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