Question

please expand (1/x + y/3) (whole cube)

Answer 1

we have to expand (1/x + y/3)³

we know,

(a + b)³ = (a + b)²(a + b)

= (a² + 2ab + b²)(a + b)

= a³ + 2a²b + ab² + a²b + 2ab² + b³

= a³ + 3a²b + 3ab² + b³

so, (1/x + y/3)³ = (1/x)³ + 3(1/x)²(y/3) + 3(1/x)(y/3)² + (y/3)³

= 1/x³ + y/x² + y²/3x + y³/27

hence, (1/x + y/3)³ = 1/x³ + y/x² + y²/3x + y³/27

Answer 2

Step-by-step explanation:

please make my answer as brainliest