Please explain AM is a median of a triangle ABC.
Is AB + BC + CA>2AM
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In ∆ ABM,
AB+BM >AM (as the sum of two sides of a triangle is greater than the third side )............1
Similarly In ∆AMC,
AC +MC >AM............2
From equation 1 and 2 we get,,,
AB+BM+AC+MC > AM+ AM
AB + BC+CA > 2AM .......(proved).
Hope that this may help you ....
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