Question

Please explain it correctly


I will mark you as brainlist

Please answer it very fast

Tomorrow is my exam

Answer 1

Hello user

It will be equal to...

(x^20/4)^1/5 = x^p

x^5/5 = x^p

x^1 = x^p


Since, bases are same so, we can compare the power

And , we get..

p= 1

Hope it works

Answer 2

$Given : \sqrt[5]{\sqrt[4]{x^{20}}} = x^p$

On squaring both sides, we get

$= > (\sqrt[5]{\sqrt[4]{x^{20}}})^2 = (x^p)^2$

$= > (\sqrt[5]{x^{\frac{20}{4}}})^2 = x^{2p}$

$= > (\sqrt[5]{x^5})^2 = (x)^{2p}$

$= > (x)^2 = (x)^{2p}$

⇒ 2 = 2p

⇒ p = 2/2

⇒ p = 1.

Therefore, the value of p = 1.

Hope this helps!