please explain me how this came. #Class 12 Vector Algebra
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the direction ratios of the normal to the plane is a,b,c
{
From the equation (r-p).N = 0
where N = ai + bj + ck
}
thus a vector perpendicular to the plane is
ai + bj + ck
also the plane perpendicular to the given plane has normal equal to 3i + j - k
since the planes are perpendicular so the normals are also perpendicular.
we can use dot product which will be equal to zero if the lines are perpendicular.
So (ai + bj + ck ). (3i +j -k) = 0
= 3a + b - c = 0
{
From the equation (r-p).N = 0
where N = ai + bj + ck
}
thus a vector perpendicular to the plane is
ai + bj + ck
also the plane perpendicular to the given plane has normal equal to 3i + j - k
since the planes are perpendicular so the normals are also perpendicular.
we can use dot product which will be equal to zero if the lines are perpendicular.
So (ai + bj + ck ). (3i +j -k) = 0
= 3a + b - c = 0
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