Please explain me how to find out the zeros of cubic polynomials? Give an example and also verify its relationship with alpha, beta, and gamma.
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to find zeros for cubic polynomial let us take x³-3x²+2x
now take x common
x(x²-3x+2)
since x²+3x+2 is in quadratic form equatic it to zero and expand it
x(x{x-2}-1{-2}
x({x-2}{x-1})
so the three zeros are 1,2, and 0.
relation between alpha,beta and gama is
sum of zeros=alpha+beta+gama=-b/a
sum of product of 2 zeros=c/a
product of zeros=-d/a
now take x common
x(x²-3x+2)
since x²+3x+2 is in quadratic form equatic it to zero and expand it
x(x{x-2}-1{-2}
x({x-2}{x-1})
so the three zeros are 1,2, and 0.
relation between alpha,beta and gama is
sum of zeros=alpha+beta+gama=-b/a
sum of product of 2 zeros=c/a
product of zeros=-d/a
Anonymous:
Thanks a lot dear
I understood it now : )
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