Question

Please explain me how to find the roots of a cubic equation...like
X^3 - 6x^2-15x-8 = 0

Answer 1

Answer:

(x+1)*(x+1)*(x-8)=0

Step-by-step explanation:

First by hit and trial take different values of x for which value of polynomial becomes zero.

For x=-1 value becomes zero. So x+1=0 is factor of the polynomial.

Now on dividing polynomial by x+1 we get x^2-7x-8=0 which is (x+1)*(x-8).

So we get factors (x+1)*(x+1)*(x-8)=0