Please explain. pls i need explanation,,,,!!! pls In a closed container, combustion of 50 mL methane is carried out with 150 ml of air containing 21% of oxygen. What will be the total volume of gaseous mixture after reaction ? CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)
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Answer:
20 ml
Explanation:
The reaction is CH4+2O2→CO2+2H2O.
At room temperature, water will condense to form liquid water.
1 mole of methane reacts with 2 moles of oxygen to form 1 mole of oxygen.
10 ml (0.445 moles) of methane will react with 20 ml (0.89 moles) of oxygen to form 10 ml (0.445 moles) of carbon dioxide.
Hence, the resulting mixture will contain 10 ml of unreacted methane and 10 ml of carbon dioxide.
The total volume of the mixture will be 20 ml.
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Answer:
we have to decrease the temp of room
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