please explain the above question....
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B) (a+b)
explaination :
given, ABCD is a trapezium in which AB || CD,
angle ADC = 2 angle ABC,
AD = a cm and CD = b cm
Since the adjacent sides of trapezium are supplementry,
ADC + ABC= 180°
3ABC = 180°
Also ABC =60°, BAD=60°
and ADC=120°, CBA=120°
(refer given attachment for diagram)
Draw a perpendicular DM bisecting AB, then triangle ADM is formed with DAM =60°.
cos60 = 1/2= AM/AD
Hence AM/a=1/2 and AM=a/2
Similarly the other side perpendicular CN is drawn and cos60 BN = a/2
The remaining part is same as b.
AB = a/2 + a/2 + b = (a+b)
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