Question

please explain the answer correctly
CORRECTLY CORRECTLY
$if \\ ( {a}^{2} - {b}^{2} ) \sin\alpha \: + 2ab \cos\alpha = {a}^{2} + {b}^{2} \\ so \: \: proved \: \: that \\ tan \alpha = \frac{ {a}^{2} - {b}^{2} }{2ab}$
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Answer 1

Answer:

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