Question

please explain the solution ​

Answer 1

Answer:

Given problem,

Let,

⇒ x = - 1  or x = 2,

x = - 1  is not possible, because value of square root of a number can not be negative,

Step-by-step explanation:

Answer 2

Step-by-step explanation:

$\sqrt{2 \sqrt{2 \sqrt{2 \sqrt{2 \sqrt{2} } } } } = x(says) \\ squaring \: on \: both \: side \\ \sqrt{2 \sqrt{2 \sqrt{2 \sqrt{2 \sqrt{2} } } } } = {x}^{2} \\ 2x = {x}^{2} \\ 2 = {x}^{2} - x \\ 2 = \times$

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