Question

please explain these questions...

Answer 1

Q.28

option D is correct........

Second ionisation energy is more or greater than first ionisation energy because first ionisation energy is the energy reqiured for removing first eletron from outer shell.

While second ionisation energy is the energy reqiured to remove the electron from inner shell of atom . Hence more energy is required to remove inner electron than outer electron




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Ionization energy, in general, increases with decrease in the atomic radius across the period from left to right. 



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because Mg is smaller than Na and has greater effective nuclear charge. Hence the first ionization energy of Mg is higher.


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It is because of stable octet configuration of Mg2+ formed after removing two electrons from Mg.

Answer 2

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28)

The I.P energy required to take out electron from noble gases configuration are always huge.

Thus there will be maximum value difference of the I.P. Energy from removal of 1st and 2nd electron would be in an element which are in Group 1.

Na, K, and Li are group 1 elements and Mg is group 2 element.

So the energy difference will be minimum on element Mg.

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♥️Hence (D) is the required answer♥️
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29)

As per above reason, there will be maximum energy required to remove electron from noble gas configuration.

Thus here the maximum difference of I.P. can be seen at the 4th electron removal.

So, there are electrons in the valence such that the 4th electron lies at the noble gas configuration.

Thus the valence electrons are 3.
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♥️Hope this is ur required answer♥️

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