Math, asked by bookwormz, 1 year ago

please explain this....i can't solve it​

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Answered by Grimmjow
26

Given : x² = y + z

\mathsf{\implies x = \dfrac{y + z}{x}}

Given : y² = x + z

\mathsf{\implies y = \dfrac{x + z}{y}}

Given : z² = y + x

\mathsf{\implies z = \dfrac{y + x}{z}}

\mathsf{Now,\;Consider :\;\dfrac{1}{x + 1} + \dfrac{1}{y + 1} + \dfrac{1}{z + 1}}

Substituting the values of x , y , z in above expression, We get :

\mathsf{\implies \dfrac{1}{\bigg[\dfrac{y + z}{x}\bigg] + 1} + \dfrac{1}{\bigg[\dfrac{z + x}{y}\bigg] + 1} + \dfrac{1}{\bigg[\dfrac{x + y}{z}\bigg] + 1}}

\mathsf{\implies \dfrac{1}{\bigg[\dfrac{y + z + x}{x}\bigg]} + \dfrac{1}{\bigg[\dfrac{z + x + y}{y}\bigg]} + \dfrac{1}{\bigg[\dfrac{x + y + z}{z}\bigg]}}

\mathsf{\implies \dfrac{x}{x + y + z} + \dfrac{y}{x + y + z} + \dfrac{z}{x + y + z}}

\mathsf{\implies \dfrac{x + y + z}{x + y + z}}

\mathsf{\implies 1}


Swarnimkumar22: nice
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