Question

Please explain with working

The change in momentum is 1.52 kgm/s for a ball that strikes the floor for 1.05 × 10^–2 s. Find the force applied to the ball. *

1.60 × 10^–2 N
145 N
1.60 N
23.8 N

Answer 1

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Answer 2

Answer:

Explanation:

Concept:

The concept of momemtum will be used to solve this question.A moving body's momemtum, which is generally equal to the product of the body's mass and velocity, is a quality that the body has as a result of its mass and motion.

Given :

The change in momemtum is $1.52 kgm/s$ and the ball that strikes the floor for $1.05 \times 10^{-2} s$ .

To Find:

We have to find the force which will be applied to the ball.

Solution:

The change of momemtum is $\Delta \mathrm{P}$ .

The value of $\Delta \mathrm{P}$ is $1.52 kgm/s$ .

The ball strikes the floor for $\Delta \mathrm{t}$ time.

The value of $\Delta \mathrm{t}$ is $1.05 \times 10^{-2} s$ .

The definition of force is the rate of momentum change.

The formula of the force is $F=\frac{\Delta P}{\Delta t}$

Put the values in the above equation to get the force.

$F=\frac{\Delta P}{\Delta t}=\frac{1.52}{1.05 \times 10^{-2}}=144.76 \mathrm{~N}$

The approximate value of the force is $145 N$ .

The option (b) is the correct answer.

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