Question

Please explen me full answer clearly.​

Answer 1

Answer:

(2/3m)^+ (3n/2)^2+2*2m/3*3n/2

Answer 2

We can solve this using the Identity:

$(a+b)^2 = a^2 + b^2 + 2ab$

For our question,

$a = \frac{2m}{3}$, $b = \frac{3n}{2}$
So,

$(\frac{2m}{3})^2 + (\frac{3n}{2})^2 + 2(\frac{2m}{3})(\frac{3n}{2})$
[tex]\frac{4m^2}{9} + \frac{9n^2}{4} + \frac{2*2m*3n}{3*2} [/tex]
[tex]\frac{4m^2}{9}+ \frac{9n^2}{4} + \frac{12mn}{6} [/tex]
$\frac{4m^2}{9} + \frac{9n^2}{4} + 2mn$

And that's our answer! Hope this Helped, and hope you're clear about the steps as well