please factories this question,see pic.
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Q. Factorize 27x³ - 125y³.
= 27x³ - 125y³
= ( 3x )³ - ( 5y )³
Using identity,
( a³ - b³ ) = ( a - b ) ( a² + b² + ab )
= ( 3x - 5y ) { ( 3x )² + ( 5y )² + 3x × 5y }
= ( 3x - 5y ) ( 9x² + 25y² + 15xy )
Hope it helps !
Q. Factorize 27x³ - 125y³.
= 27x³ - 125y³
= ( 3x )³ - ( 5y )³
Using identity,
( a³ - b³ ) = ( a - b ) ( a² + b² + ab )
= ( 3x - 5y ) { ( 3x )² + ( 5y )² + 3x × 5y }
= ( 3x - 5y ) ( 9x² + 25y² + 15xy )
Hope it helps !
kartikprajapat:
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here's your answer....
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